6=(1/36)^2x+3

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Solution for 6=(1/36)^2x+3 equation: 



6=(1/36)^2x+3

We move all terms to the left:

6-((1/36)^2x+3)=0



Domain of the equation: 36)^2x+3)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+1/36)^2x+3)+6=0

We multiply all the terms by the denominator


-((+1+6*36)^2x+3)=0



We calculate terms in parentheses: -((+1+6*36)^2x+3), so:

(+1+6*36)^2x+3

We add all the numbers together, and all the variables

217^2x+3

Back to the equation:

-(217^2x+3)



We get rid of parentheses

-217^2x-3=0

We move all terms containing x to the left, all other terms to the right

-217^2x=3

x=3/1

x=3

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